It's known that a cube can be made of 5 tetrahedra: *1 regular tetrahedron* at the center, plus *4 trirectangular tetrahedra* (*trt*) glued to the 4 faces of the former.
If the edge of the cube be 2, the edges of the *regular tetrahedron* (in the interior) will have length = 2.sqrt(2) & its volume will be 8/3. Now, the *trt* has the same base as a face of the reg. tetrahedron & 1/2 its altitude, so its volume is 4/3. Together:
8/3 (reg. tetrah.) + 4. 4/3 (trt's)= 24/3 = 8 (volume of the cube)
@isaacc Confused, but lovin' it.
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